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(D) . $CH_3-CN$ reacts with $AlH(i-Bu)_2$ ($DIBAL$-$H$) followed by hydrolysis to give $CH_3CHO$ (acetaldehyde).$B$. $CH_3COCl$ undergoes Rosenmund re

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$CH_3-C \equiv N \xrightarrow[(ii) H_2O]{(i) LiAlH_4}$

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(D) . $CH_3-CN$ reacts with $AlH(i-Bu)_2$ ($DIBAL$-$H$) followed by hydrolysis to give $CH_3CHO$ (acetaldehyde).$B$. $CH_3COCl$ undergoes Rosenmund reduction with $H_2-Pd/BaSO_4$ to produce $CH_3CHO$.$C$. $HC \equiv CH$ undergoes hydration in the presence of $HgSO_4/H_2SO_4$ to form vinyl alcohol,which tautomerizes to $CH_3CHO$.$D$. $CH_3-CN$ is reduced by $LiAlH_4$ to form ethylamine $(CH_3-CH_2-NH_2)$,not acetaldehyde. Therefore,option $D$ is the correct answer.

Which of the following reactions will not produce acetaldehyde?

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Which of the following is a Stephen reaction?

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